5c) I originally had the equation of this graph as 3sin15x-8. The correct answer is 3sin30x+9. My answer was wrong because when calculating the period, I only calculated half of a period. My vertical shift was wrong because I counted wrong.
5d) I originally had the equation of this graph as 2sec1/2(x-2). I don't know how to find the equation of secant graphs, so I got this pretty much completely wrong. The correct answer is -3csc(x/2). For this problem, it is easier to use cosecant. The amplitude of -3 can be found by plugging in points. The b value is 1/2 because the period is 4pi, or 2 times the normal period of 2pi.
I struggled with this section. I could find the graphs of sine and cosine fairly well, but tangent, cotangent, secant and cosecant were difficult. I never really learned algebraically how to find these graphs. I didn't really get how to plug in points to find an equation.
